Token Passing Utilization - Best Case
Now if a > 1 then time to send frame is still 1 but can start sending token after ìaî since that is when the sending station begins to receive its own frame, ie, T1 + T2 = a + a/ N, thus
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- U = 1/ a(1+1/ N) if a > 1
- U = 1/ (1 + a/ N) if a < 1
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if N is large then
- U = 1 if a < 1
- U = 1/ a if a > 1